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Re: Math problem From: Richard Chudacoff, MD (rchudacoff@mylinuxisp.com) Wed Aug 30 17:19:34 2000 Messages sorted by: [ date ][ thread ][ subject ][ author ] Next message: DoctorJoe@aol.com: "Re: resistant Trichomoniasis" Previous message: Richard Chudacoff, MD: "Re: resistant Trichomoniasis" In reply to: DoctorJoe@aol.com: "FRI: Math problem" Next in thread: Zach Newton: "Re: FRI: Math problem" Seems like he was greater than, not equal to. LOL Rick -----Original Message----- From: ob-gyn-l@obgyn.net [mailto:ob-gyn-l@obgyn.net]On Behalf Of DoctorJoe@aol.com Sent: Wednesday, August 30, 2000 5:04 PM To: Multiple recipients of list OB-GYN-L Subject: FRI: Math problem Always wondered where that formula came from... Joe P. > There were three medieval kingdoms on the shores of a lake. > There was an island in the middle of the lake, which the > kingdoms had been fighting over for years. Finally, the three > kings decided that they would send their knights out to do > battle, and the winner would take the island. > > The night before the battle, the knights and their squires > pitched camp and readied themselves for the fight. The first > kingdom had 12 knights, and each knight had five squires, all of > whom were busily polishing armor, brushing horses, and cooking > food. The second kingdom had 20 knights, and each knight had 10 > squires. Everyone at that camp was also busy preparing for > battle. At the camp of the third kingdom, there was only one > knight, with his squire. This squire took a large pot and hung > it from a looped rope in a tall tree. He busied himself > preparing the meal, while the knight polished his own armor. > > When the hour of the battle came, the three kingdoms sent their > squires out to fight (this was too trivial a matter for the > knights to join in). The battle raged, and when the dust > cleared, the only person left was the lone squire from the third > kingdom, having defeated the squires from the other two kingdoms, > thus proving... > that the squire of the high pot and noose is equal > to the sum of the squires of the other two sides. Next message: DoctorJoe@aol.com: "Re: resistant Trichomoniasis" Previous message: Richard Chudacoff, MD: "Re: resistant Trichomoniasis" In reply to: DoctorJoe@aol.com: "FRI: Math problem" Next in thread: Zach Newton: "Re: FRI: Math problem"

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